mazorj

In Vista 64 home premium SP1, in running chkdsk for C: at the end it states that there are 85,144,492 "total allocation units on disk" but the next line says there are 187,552 "allocation units available on disk". No disk errors were found.

1. What are allocation units and why are they there?

2. Does this mean I'm running out of allocation units? If 187,552 represents 0.22% of the 85,144,492, then are 99.78% of the total allocation units on the disk already in use and therefore not available for writing new files in the directories?

3. Will I hit some kind of brick wall here? If so, is there some way to free up allocation units before that happens?