Vista - Is there a way to control the angle of a lineargradient?

I have added a lineargradient to a rectangle. I have specified the direction
of the gradient as StartPoint=0,0 to EndPoint=1,1. When I change the shape of
the rectangle, the lineargradient changes its direction because it's drawn
from 0,0 to 1,1 of the bounding rectangle. Is there a way to control the
angle of the lineargradient so that it is always 45 degrees? I want the
angle of the gradient to be the same no mather what size the rectangle is.
TIA.

Yes, now my linear gradient is always at 45 degrees. However, the gradient
does not fill the element equally. This is because the gradient is rotated
about 0,0 instead of half the width, half the height of the element. It
would be nice if on the RotateTransform I could specify CenterX=0.5 and
CenterY=0.5 as half the bounding area of the element. However, I have to
specify half the width and height, which is only known at runtime. Any
suggestions?

"Adam Smith [MS]" wrote:

> The easiest way to do this is to start with a horizontal linear gradient and
> then rotate it 45 degrees:
>
> <LinearGradientBrush StartPoint="0,0" EndPoint="1,0">
> <LinearGradientBrush.Transform>
> <RotateTransform Angle="45"/>
> </LinearGradientBrush.Transform>
> </LinearGradientBrush>
>
> -Adam Smith [MS]
>
> "Gary F" <GaryF@discussions.microsoft.com> wrote in message
> newsE30A7EA-DAD8-4AC6-938F-9313F1F0643A@microsoft.com...
> >I have added a lineargradient to a rectangle. I have specified the
> >direction
> > of the gradient as StartPoint=0,0 to EndPoint=1,1. When I change the shape
> > of
> > the rectangle, the lineargradient changes its direction because it's drawn
> > from 0,0 to 1,1 of the bounding rectangle. Is there a way to control the
> > angle of the lineargradient so that it is always 45 degrees? I want the
> > angle of the gradient to be the same no mather what size the rectangle is.
> > TIA.
>
>
>

Gary,

Use the RelativeTransform property instead of the Transform property and you
can specify the relative center of the rotation:

<LinearGradientBrush StartPoint="0,0" EndPoint="1,0">

<LinearGradientBrush.RelativeTransform>
<RotateTransform Angle="45" CenterX="0.5" CenterY="0.5" />
</LinearGradientBrush.RelativeTransform>
</LinearGradientBrush>

****
Mike Jacobs [MSFT]
This posting is provided "AS IS" with no warranties, and confers no rights.


"Gary F" <GaryF@discussions.microsoft.com> wrote in message
news:5E7ED7D3-B4E1-4441-AFAD-8E397CCF9E62@microsoft.com...
> Yes, now my linear gradient is always at 45 degrees. However, the
> gradient
> does not fill the element equally. This is because the gradient is
> rotated
> about 0,0 instead of half the width, half the height of the element. It
> would be nice if on the RotateTransform I could specify CenterX=0.5 and
> CenterY=0.5 as half the bounding area of the element. However, I have to
> specify half the width and height, which is only known at runtime. Any
> suggestions?
>
> "Adam Smith [MS]" wrote:
>
>> The easiest way to do this is to start with a horizontal linear gradient
>> and
>> then rotate it 45 degrees:
>>
>> <LinearGradientBrush StartPoint="0,0" EndPoint="1,0">
>> <LinearGradientBrush.Transform>
>> <RotateTransform Angle="45"/>
>> </LinearGradientBrush.Transform>
>> </LinearGradientBrush>
>>
>> -Adam Smith [MS]
>>
>> "Gary F" <GaryF@discussions.microsoft.com> wrote in message
>> newsE30A7EA-DAD8-4AC6-938F-9313F1F0643A@microsoft.com...
>> >I have added a lineargradient to a rectangle. I have specified the
>> >direction
>> > of the gradient as StartPoint=0,0 to EndPoint=1,1. When I change the
>> > shape
>> > of
>> > the rectangle, the lineargradient changes its direction because it's
>> > drawn
>> > from 0,0 to 1,1 of the bounding rectangle. Is there a way to control
>> > the
>> > angle of the lineargradient so that it is always 45 degrees? I want
>> > the
>> > angle of the gradient to be the same no mather what size the rectangle
>> > is.
>> > TIA.
>>
>>
>>