Vista - TemplateBinding with Image Source Property

Hi~~


I want to binding a image from dependency property of the control
I use template binding to bind a path which is string-type


<Style x:Key="{x:Type local:BitmapButton}" TargetType="{x:Type
local:BitmapButton}">
<Setter Property="Template">
<Setter.Value>
<ControlTemplate TargetType="{x:Type local:BitmapButton}">
<Grid x:Name="Grid" >
<ColumnDefinition/>
<RowDefinition/>
<Image Source=
"{TemplateBinding local:BitmapButton.ImageDefault} Width="Auto"
Height="Auto"/>
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ It
doesn't work

<TextBlock x:Name="ImagePath"
Text="{TemplateBinding
local:BitmapButton.ImageDefault}"/>

^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ it works
<ContentPresenter ...
</Grid>
</ControlTemplate>
</Setter.Value>
</Setter>
</Style>

I have no idea why Image does not work but TextBlock's Text work.
Any suggestions? :-(

Thanks

HolaMan

HolaMan wrote:

> I have no idea why Image does not work but TextBlock's Text work. Any
> suggestions? :-(

It doesn't work because Image's Source property is not of type string, it
is of type ImageSource. The only reason you can put a string there in XAML
is because when XAML is parsed, the parser uses the converter architecture
to translate the string into a real ImageSource. At runtime though, when
the Binding is occuring, it's gotta be a real ImageSource instance. Therefore,
if your datasource is providing you with a string, you'll need to implement
an IValueConverter[1] to translate that string into a real ImageSource. My
recommendation would be to simply use the ImageSourceConverter's[2] ConvertFrom
method inside of your IValueConverter's Convert implementation.

HTH,
Drew

[1] http://windowssdk.msdn.microsoft.com...eConverter.asp
[2] http://windowssdk.msdn.microsoft.com...eConverter.asp
___________________________________
Drew Marsh
Chief Software Architect
Mimeo.com, Inc. - http://www.mimeo.com
Microsoft C# / WPF MVP
Weblog - http://blog.hackedbrain.com/

Thanks for your reply. I will try it.