Vista Tutorial - WCF: How to reference a service that runs in the same process?

Hi,

I'm building a service that can act both client and server (two servers can
communicate each others).

How can I set my project in order to create the service reference ?

thanks,
Steve

If you mean, that you want to communicate from one service with another, you
can use proxy exactly as client or create channel to second service's entry
point directly :
channelFactory = new ChannelFactory<YouSecondServiceInterface>(binding,
address);

YouSecondServiceInterface channel = channelFactory.CreateChannel();

Arkady

"Steve B." <steve_beauge@com.msn_swap_msn_and_com> wrote in message
news:e0JW4T18GHA.4304@TK2MSFTNGP03.phx.gbl...
> Hi,
>
> I'm building a service that can act both client and server (two servers
> can communicate each others).
>
> How can I set my project in order to create the service reference ?
>
> thanks,
> Steve
>

Let's expose the scenario...

I want to build a service that runs on multiple serveurs. These services can
send data to other instances of the service on other computer.

The sent data is selected by an administrator in a windows app.

We have :

Admin computer : run a windows app which is client of "SourceService"
Server A : run a host which is client of "DestinationService" and host
"DestinationService" and "SourceService"
Server B : run a host which is client of "DestinationService" and host
"DestinationService" and "SourceService"

The source service have a method like : SendData(Data myData, string
remoteServer)
The destination service have a methode like : ReceiveData(Data myDate);

Inside this method, I have something like this:

string remote = BuildUri(uriFormat, remoteserver); // build the correct
remote uri

DestinationServiceClient proxy = new DestinationServiceClient(remote);

proxy.ReceiveData(Data myData);


However, the last line "proxy.ReveiveData" throw an exception 400: bad
request.

I also try this code :
IDestination destProxy = ChannelFactory<IDestination>.CreateChannel(

new WSHttpBinding(),

new EndpointAddress(remoteUri)

);

destProxy.ReceiveData(myData);



But I get the same behaviour...

"Arkady Frenkel" <arkadyf@hotmailxdotx.com> a écrit dans le message de news:
OSjzAO28GHA.4996@TK2MSFTNGP03.phx.gbl...
> If you mean, that you want to communicate from one service with another,
> you can use proxy exactly as client or create channel to second service's
> entry point directly :
> channelFactory = new ChannelFactory<YouSecondServiceInterface>(binding,
> address);
>
> YouSecondServiceInterface channel = channelFactory.CreateChannel();
>
> Arkady
>
> "Steve B." <steve_beauge@com.msn_swap_msn_and_com> wrote in message
> news:e0JW4T18GHA.4304@TK2MSFTNGP03.phx.gbl...
>> Hi,
>>
>> I'm building a service that can act both client and server (two servers
>> can communicate each others).
>>
>> How can I set my project in order to create the service reference ?
>>
>> thanks,
>> Steve
>>
>
>

That exact scenario of router example from
http://windowssdk.msdn.microsoft.com...97(VS.80).aspx
I prefer second way - direct channel without proxy because both sides know
each other in my case
Arkady


"Steve B." <steve_beauge@com.msn_swap_msn_and_com> wrote in message
news:%23geTCb28GHA.4604@TK2MSFTNGP03.phx.gbl...
> Let's expose the scenario...
>
> I want to build a service that runs on multiple serveurs. These services
> can send data to other instances of the service on other computer.
>
> The sent data is selected by an administrator in a windows app.
>
> We have :
>
> Admin computer : run a windows app which is client of "SourceService"
> Server A : run a host which is client of "DestinationService" and host
> "DestinationService" and "SourceService"
> Server B : run a host which is client of "DestinationService" and host
> "DestinationService" and "SourceService"
>
> The source service have a method like : SendData(Data myData, string
> remoteServer)
> The destination service have a methode like : ReceiveData(Data myDate);
>
> Inside this method, I have something like this:
>
> string remote = BuildUri(uriFormat, remoteserver); // build the correct
> remote uri
>
> DestinationServiceClient proxy = new DestinationServiceClient(remote);
>
> proxy.ReceiveData(Data myData);
>
>
> However, the last line "proxy.ReveiveData" throw an exception 400: bad
> request.
>
> I also try this code :
> IDestination destProxy = ChannelFactory<IDestination>.CreateChannel(
>
> new WSHttpBinding(),
>
> new EndpointAddress(remoteUri)
>
> );
>
> destProxy.ReceiveData(myData);
>
>
>
> But I get the same behaviour...
>
> "Arkady Frenkel" <arkadyf@hotmailxdotx.com> a écrit dans le message de
> news: OSjzAO28GHA.4996@TK2MSFTNGP03.phx.gbl...
>> If you mean, that you want to communicate from one service with another,
>> you can use proxy exactly as client or create channel to second service's
>> entry point directly :
>> channelFactory = new ChannelFactory<YouSecondServiceInterface>(binding,
>> address);
>>
>> YouSecondServiceInterface channel = channelFactory.CreateChannel();
>>
>> Arkady
>>
>> "Steve B." <steve_beauge@com.msn_swap_msn_and_com> wrote in message
>> news:e0JW4T18GHA.4304@TK2MSFTNGP03.phx.gbl...
>>> Hi,
>>>
>>> I'm building a service that can act both client and server (two servers
>>> can communicate each others).
>>>
>>> How can I set my project in order to create the service reference ?
>>>
>>> thanks,
>>> Steve
>>>
>>
>>
>
>