I have an ArrayList outputList. I only need to get the last item:

int last = outputList.LastIndexOf(null);
ExtremeBucket lastItem =
(ExtremeBucket)outputList[last];

Please confirm if this is the right way. Thanks!

No, to get the last item in the list, use

int last = outputList [outputList.Count () - 1];

I have no idea how you are converting an int to an ExtremeBucket though.

"Curious" <fir5tsight@xxxxxx> wrote in message
news:2cccbb3d-cbdd-49e6-8b76-992404df2fa0@xxxxxx

>I have an ArrayList outputList. I only need to get the last item:
>
> int last = outputList.LastIndexOf(null);
> ExtremeBucket lastItem =
> (ExtremeBucket)outputList[last];
>
> Please confirm if this is the right way. Thanks!

Family Tree Mike:

Thanks! FYI, I used the following approach you've suggested:

ExtremeBucket lastItem =
(ExtremeBucket)outputList[outputList.Count - 1];

Each item is type of ExtremeBucket.

On Fri, 24 Oct 2008 14:39:50 -0700 (PDT), Curious
<fir5tsight@xxxxxx> wrote:

>Family Tree Mike:
>
>Thanks! FYI, I used the following approach you've suggested:
>
> ExtremeBucket lastItem =
>(ExtremeBucket)outputList[outputList.Count - 1];
>
>Each item is type of ExtremeBucket.

You should consider using the generic List instead of ArrayList. That
way your access to the list will be type safe.

I agree with Jack, that List<ExtremeBucket> will be better for you in the
long run.

"Curious" <fir5tsight@xxxxxx> wrote in message
news:691b4373-6e3e-445a-a9e0-8083992fcd40@xxxxxx

> Family Tree Mike:
>
> Thanks! FYI, I used the following approach you've suggested:
>
> ExtremeBucket lastItem =
> (ExtremeBucket)outputList[outputList.Count - 1];
>
> Each item is type of ExtremeBucket.

> I agree with Jack, that List<ExtremeBucket> will be better for you in the
> long run.

I do intend to use List<ExtremeBucket>. However, since this must be
coded in Visual Studio 2003 (which is compatible with .NET 1.1), I
have to use ArrayList because it doesn't recognize generic.