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| | #1 (permalink) |
| | How do I get from the sine of an angle to the actual angle I have been struggling with this for several days but have been unable to do it. I have downloaded and installed the VB Express Edition 2008 so that I could use the "truncate" method. For example, in a right triangle with opposite side of 6.0, adjacent side of 8.0, and a hypotenuse of 10.0 the sine of theta is 6.0 / 10.0 or 0.6. This gives me the sine of the angle but just how do I get the angle whose sine is 0.6? I can look it up in the Trig tables but I need to be able to do it with DOTNET program code. I sure need some help on this and thanks in advance for any help. -- JungleJim74 |
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| | #2 (permalink) |
| | RE: How do I get from the sine of an angle to the actual angle "JungleJim74" wrote: Quote: > I have been struggling with this for several days but have been unable to do > it. I have downloaded and installed the VB Express Edition 2008 so that I > could use the "truncate" method. For example, in a right triangle with > opposite side of 6.0, adjacent side of 8.0, and a hypotenuse of 10.0 the sine > of theta is 6.0 / 10.0 or 0.6. This gives me the sine of the angle but just > how do I get the angle whose sine is 0.6? I can look it up in the Trig tables > but I need to be able to do it with DOTNET program code. I sure need some > help on this and thanks in advance for any help. > -- > JungleJim74 That returns radians, so you may need to convert depending on your application. You should look into the documentation here: http://msdn.microsoft.com/en-us/libr...h_methods.aspx Mike |
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