Vista - How do I get from the sine of an angle to the actual angle

I have been struggling with this for several days but have been unable to do
it. I have downloaded and installed the VB Express Edition 2008 so that I
could use the "truncate" method. For example, in a right triangle with
opposite side of 6.0, adjacent side of 8.0, and a hypotenuse of 10.0 the sine
of theta is 6.0 / 10.0 or 0.6. This gives me the sine of the angle but just
how do I get the angle whose sine is 0.6? I can look it up in the Trig tables
but I need to be able to do it with DOTNET program code. I sure need some
help on this and thanks in advance for any help.
--
JungleJim74

"JungleJim74" wrote:
Use Math.Asin(0.6)

That returns radians, so you may need to convert depending on your
application.

You should look into the documentation here:
http://msdn.microsoft.com/en-us/libr...h_methods.aspx

Mike