Using param with InvokeReturnAsIs

I can't seem to use param when invoking a scriptblock using
InvokeReturnAsIs. Also, the same problem occurs when using a
PSScriptMethod. Here are some examples of what works and does not
work.

First the Easy:
&{param($x,$Y) Write-Host "v1 X: $x Y:$y"; $x+$y} 5 6

v1 X: 5 Y:6
11

This demonstrates params come in as Args:
$script2 = [scriptBlock] { $x = $Args[0]; $y = $Args[1]; Write-Host
"v2 X: $x Y:$y"; $x+$y}
&$script2 9 10

v2 X: 9 Y:10
19

$script2.InvokeReturnAsIs(11,12)

v2 X: 11 Y:12
23

Now with a param statement:
$script3 = [scriptBlock] { param($x,$y); Write-Host "v3 X: $x Y:$y"; $x
+$y}
&$script3 13 14

v3 X: 13 Y:14
27

$script3.InvokeReturnAsIs(15,16)

v3 X: Y:


All works as expected except for the last call.

Is there any fix or work around?

Works fine for me :

PS > $script3 = [scriptBlock] { param($x,$y); Write-Host "v3 X: $x Y:$y";
$x+$y}
PS > $script3.InvokeReturnAsIs(15,16)
v3 X: 15 Y:16
31

PS > $script3.Invoke(15,16)
v3 X: 15 Y:16
31



-----
Shay Levi
$cript Fanatic
http://scriptolog.blogspot.com

BTW, why not writing it as a function?

-----
Shay Levi
$cript Fanatic
http://scriptolog.blogspot.com
PS>> $script3 = [scriptBlock] { param($x,$y); Write-Host "v3 X: $x
PS>> Y:$y";
PS>> PS>> $script3.InvokeReturnAsIs(15,16)
PS>> PS>> $script3.Invoke(15,16)
PS>>

On Jan 18, 8:55*am, Shay Levi <n...@xxxxxx> wrote: This is a little disturbing. What OS are you running on? I'm on
Windows 2003 Server.

As to why I'm needing to invoke a script, it's not worth digging into
the problem set. But as I said I get the same problem with
PSScriptMethod
How does this work for you?

$object = new-object Management.Automation.PSObject

$script1 = [scriptBlock] { param($x,$y); Write-Host "Method1 X: $x Y:
$y"; $x+$y}
$script2 = [scriptBlock] { $x = $Args[0]; $y = $Args[1]; Write-Host
"Method2 X: $x Y:$y"; $x+$y}

$member1 = new-object management.automation.PSScriptMethod "Method1",
$script1
$object.psobject.members.Add($member1)

$member2 = new-object management.automation.PSScriptMethod "Method2",
$script2
$object.psobject.members.Add($member2)

$object.Method1(5,6)
Method1 X: Y:

$object.Method2(7,8)

Method2 X: 7 Y:8
15

I'm runing PowerShell CTP on WinXP SP2. I checked
the commands on a W3K SP1 box and it works.

As for the below, you need to *capture* the new object you created, assign
it to a new variable.


$object = new-object Management.Automation.PSObject
$script1 = [scriptBlock] { param($x,$y); Write-Host "Method1 X: $x Y: $y";
$x+$y}
$script2 = [scriptBlock] { $x = $Args[0]; $y = $Args[1]; Write-Host "Method2
X: $x Y:$y"; $x+$y}

$member1 = new-object management.automation.PSScriptMethod "Method1",$script1
$object.psobject.members.Add($member1)

$member2 = new-object management.automation.PSScriptMethod "Method2",$script2
$object.psobject.members.Add($member2)

$new = $object
$new.Method1(5,6)
Method1 X: 5 Y: 6
11

$new.Method2(7,8)
Method2 X: 7 Y:8
15



-----
Shay Levi
$cript Fanatic
http://scriptolog.blogspot.com

On Jan 18, 11:21*am, Shay Levi <n...@xxxxxx> wrote: FYI Shay et al - using named parameters in anonymous functions
(scriptblocks) is *broken* in powershell 1.0. As you can see, it`s
fixed in in 2.0 CTP.

- Oisin

On Jan 18, 10:21*am, Shay Levi <n...@xxxxxx> wrote: I executed

$new = $object
$new.Method1(5,6)

and got:

Method1 X: Y:

There has to be some explanation. I'm fairly certain I've had the
same behavior on more than one system but they are W3K

Why would I need to "Capture" the object? What happens when you run
the method on $object?

On Jan 18, 11:57*am, cashfo...@xxxxxx wrote: Hey cash,

You may have missed my other post - the explanation is simple. What
you're trying to do won't work in powershell 1.0 - its broken - a bug
- foobared. Shay is using a beta of powershell 2.0 where the problem
has been fixed. You will have to use the $args collection in anonymous
scriptblocks. Named parameters with "param" doesn`t work.

Hope this helps,

- Oisin / x0n