Directory Size using PowerShell

Hello, I have about 45 directories that have about 10 nested directories
with tens of thousands of files in the directory. I have folder compression
turned on since most of my files are .txt and I get a 2:1 compression.

I would like a Powershell script that can recurively scan a root directory
of my choosing and simply give me the total size of each directory in the
root directory, sorted from largest to smallest.

Can anyone help me with this?

Try this:


get-childitem | where {$_.PSIsContainer} | foreach {

$size = (Get-ChildItem $_ -recurse | where {!$_.PSIsContainer} | Measure-Object
-Sum Length).Sum

$obj = new-object psobject
add-member -inp $obj noteproperty path $_.fullName
add-member -inp $obj noteproperty size $size
$obj
}




-----
Shay Levi
$cript Fanatic
http://scriptolog.blogspot.com

dm3281 pisze: try something like this:

[uint64]$size=0
Get-ChildItem -Recurse | % {$size=$size+$_.Length}
$size

Also like this...

(gci C:\Folder -recurse | measure-object Length -sum).Sum



dm3281 wrote:

"dm3281" <dm3281@xxxxxx> wrote in message
news:5A22D438-3110-4295-BFD5-68EEAF6CE32A@xxxxxx If you are interested in something that is orders of magnitude faster than
the typical PowerShell solution then go grab DU.exe from the Sysinternals
site:

http://technet.microsoft.com/en-us/s.../bb896651.aspx

Remember folks to use the right tool for the job. The Filesystem provider
performance in v1.0 isn't great and it really shows on issues like this
(especially for large dir structures).

--
Keith

I was looking for a way to find my 5 biggest folders on my pc.
I've downloaded du utility and ran this command

du -v | sort -desc | select -first 5

This command gives me this result
Totals: .....
Size: .....
Size on disk: ....
Files: ....
Directory ....

So if I want to see these 5 folders I've to write

du -v | sort -desc | select -first 10

Is there a way to skip the five lines I wrote above? (like select between 6 and 10)

Moreover I have 2 partitions on my hard disk and I'd like to know if it's possible to scan them together to find the 5 biggest folders independently of the unit or if I have to run the command twice and then compares the results.
Thanks in advance.

You can do array slicing:

(du -v | sort -desc)[6..10]

- or -


$du = du -v | sort -desc
$du[6..$du.length]


---
Shay Levy
Windows PowerShell MVP
http://blogs.microsoft.co.il/blogs/ScriptFanatic



s> I was looking for a way to find my 5 biggest folders on my pc. I've
s> downloaded du utility and ran this command
s>
s> du -v | sort -desc | select -first 5
s>
s> This command gives me this result
s> Totals: .....
s> Size: .....
s> Size on disk: ....
s> Files: ....
s> Directory ....
s> So if I want to see these 5 folders I've to write
s>
s> du -v | sort -desc | select -first 10
s>
s> Is there a way to skip the five lines I wrote above? (like select
s> between 6 and 10)
s>
s> Moreover I have 2 partitions on my hard disk and I'd like to know if
s> it's possible to scan them together to find the 5 biggest folders
s> independently of the unit or if I have to run the command twice and
s> then
s> compares the results.
s> Thanks in advance.

Hi sardinian_guy,


You can do array slicing using array ranges:

(du -v | sort -desc)[6..10]

- or -

$du = du -v | sort -desc
$du[6..$du.length]





---
Shay Levy
Windows PowerShell MVP
http://blogs.microsoft.co.il/blogs/ScriptFanatic



s> I was looking for a way to find my 5 biggest folders on my pc. I've
s> downloaded du utility and ran this command
s>
s> du -v | sort -desc | select -first 5
s>
s> This command gives me this result
s> Totals: .....
s> Size: .....
s> Size on disk: ....
s> Files: ....
s> Directory ....
s> So if I want to see these 5 folders I've to write
s>
s> du -v | sort -desc | select -first 10
s>
s> Is there a way to skip the five lines I wrote above? (like select
s> between 6 and 10)
s>
s> Moreover I have 2 partitions on my hard disk and I'd like to know if
s> it's possible to scan them together to find the 5 biggest folders
s> independently of the unit or if I have to run the command twice and
s> then
s> compares the results.
s> Thanks in advance.

Thank you very much Shay.

(du -v | sort -desc)[6..10]

it's perfect. I didnt' know this trick.

I have a last question. With du I suppose that it's not possibile to use comparison operators, for instance to find all the folders that are greater than a specified size.
I hope I'm wrong.