Vista - PowerShell User Guide - Comparison Operators - error?

Is there a mistake in the section that reads as follows?
"Comparisons of types that are not the same are based on the right hand side
of the operator. The shell will attempt to convert the left hand side of
the operator into the type of the right hand side of the operator. "
My tests show the current release converts the right hand side to the left
hand side.
Example:
PS D:\> $sb1 = new-object system.text.stringbuilder test
PS D:\> $sb1 -eq "test"
False
PS D:\> "test" -eq $sb1
True
--
David K Allen
Carlson School of Management
University of Minnesota
Minneapolis, MN

yep - that's a typo - good catch!

jim

--
James Truher[MSFT]
Program Manager - Windows PowerShell
Microsoft Corporation
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"David K Allen" <David_UMN@newsgroups.nospam> wrote in message
news:3BF0C994-ED8F-455C-929F-FAFE397C2FEC@microsoft.com...
> Is there a mistake in the section that reads as follows?
> "Comparisons of types that are not the same are based on the right hand
> side
> of the operator. The shell will attempt to convert the left hand side of
> the operator into the type of the right hand side of the operator. "
> My tests show the current release converts the right hand side to the left
> hand side.
> Example:
> PS D:\> $sb1 = new-object system.text.stringbuilder test
> PS D:\> $sb1 -eq "test"
> False
> PS D:\> "test" -eq $sb1
> True
> --
> David K Allen
> Carlson School of Management
> University of Minnesota
> Minneapolis, MN