Vista - output group membership on a single line

I've been trying to figure out how to do this and I just can't seem to
figure it out. What I have is this:

(get-group -Identity <groupName>).members | select name

This returns each name on a separate line:

User1
User2
User3
User4

What I'd like is to change it to a series of strings that I can save to
a file where it looks like this:

User1,User2,User3,User4

Any thoughts on how to do this?

As always thanks for any answers or feedback.

Perfect..thanks!

Shay Levi wrote:

Hi Steven,

First strip the object to have the names (group members) as strings only,
use foreach instead of select, and assign it to a variable.
Here's an example using get-process:

PS 22> $names = gps m* | foreach {$_.name}
PS 23> $names

Maxthon
mDNSResponder
msdtc
msnmsgr
mstsc

In PowerShell v1.0 you can join the strings with [string]::join static method:


PS 24> [string]::join(",",$names)

Maxthon,mDNSResponder,msdtc,msnmsgr,mstsc


PowerShell CTP(2) has a new -join parameter, so you can do:

PS 25> $p -join ","
Maxthon,mDNSResponder,msdtc,msnmsgr,mstsc



---
Shay Levi
$cript Fanatic
http://scriptolog.blogspot.com

Hi Steven,

Here is a nice one-liner for you. :-)

(get-qadgroup -Identity <groupName>) | get-qadgroupmember |
% {$names = @()} {$names += $_.name} {[string]::join(",",$names)} |
out-file c:\temp\members.txt

-aleksandar
http://powershellers.blogpost.com


On May 22, 8:37*pm, Steven <evetsl...@xxxxxx> wrote:

What about this?

[PS] C:\>[string] ((get-group -Identity Legal).members | ForEach-Object
{$_.name})
Kim Akers Brian Cox


--
Tibor


"Steven" wrote: