Vista - Invoking Cmdlet Get-Location from cmdlet,cant get Currnt Directory

Hi
If we do a Get-location on a powershell it displays the curent working
directory. And i want the same current working Directory when i am invoking a
custom made cmdlet from prompt( in the working directory).

Ex:
C:\TesT> New-CustomCmdlet

In the above case in My custom cmdlet i want the directory name to be
"C:\Test\"
but Its gives C:\Documents and Settings\myname ( This is the directory,
which is the root directory when powershell is launched). In the
ProcessRecord the following code is writtenRunspaceInvoke invoker = new RunspaceInvoke();
foreach(PSObject result in invoker.Invoke("Get-location"))
{
Console.WriteLine(result.Members["Path"].Value);
}I tried using the above commands using Runspace configuration and changed
the processRecord to the following statement

"RunspaceConfiguration config = RunspaceConfiguration.Create();
Runspace myRunSpace = RunspaceFactory.CreateRunspace(config);
myRunSpace.Open();
Pipeline pipeLine = myRunSpace.CreatePipeline("Get-Location");
Collection<PSObject> results = pipeLine.Invoke();
foreach (PSObject result in results)
{
Console.WriteLine(result.Members["Path"].Value);
}
"

Then also the result was same C:\Documents and Settings\myname.

How to i get the current working Directory from where i launch the cmdlet?
Or is there any bug in powershell related to this

Any help will be greatly appreciated.

Thanks

On Jun 5, 3:17 pm, Vikram <Vik...@xxxxxx> wrote:Vikram,

Try SessionState.Path.CurrentFileSystemLocation.Path.

Jeff

Hi Jeff

It works!!!!

Thanks
vikram

"Jeff" wrote: