Vista - count number of files

Hi guys. I need your help because I'm not able to solve a problem.

Let's suppose I have a folder like this

folder1
folder2
...
folderN
file1
file2
...
fileN

I want to count the number of files inside my folders, that is the total of files of folder1+folder2+folderN without counting file1,file2 and so on.
Thanks in advance.

I've solved on my own.

$folders = gci | ? {-$_.psiscontainer}
$tot=0;foreach($folder in $folders) {$tot = $tot +(gci $folder).count}
$tot

I'm a newbie but I love powershell.
Thanks the same. Have a nice day.

Hi sardinian_guy,


Glad you could resolve it yourself. I would like to add one thing, one Powershell
gotcha to be aware of:

In PowerShell, if your command results in one object only (scalar) then there
is no count property available. Therefor, trying to count
a directory that has only one child item will yield nothing. To make the
result (any result) have a count property, force it to array @(), as in:

@(gci $folder).count


That's a very important rule of thumb, remember it



BTW, if you want your command to include hidden files too, add the -force
parameter to gci.


---
Shay Levi
$cript Fanatic
http://scriptolog.blogspot.com

s> I've solved on my own.
s>
s> $folders = gci | ? {-$_.psiscontainer}
s> $tot=0;foreach($folder in $folders) {$tot = $tot +(gci
s> $folder).count}
s> $tot
s> I'm a newbie but I love powershell. Thanks the same. Have a nice day.
s>
s>

Hi Shay.
I didn't know this thing.
I created a folder with just one file within and indeed it doesn't give me any result. If I add another file it returns correctly two. Thank you very much for this trick and for all your useful posts. I'm learning a lot of interesting things reading you and other great users of this forum.
Thanks again and sorry for my english.