Vista - Retrieve the path of the file

Hi,

I have a requirement where in I know the name of the file. But do not know
the complete path of its location. Moreover the machine will be having
atleast 3 drives. Is there any way to retrieve the path of the specified File
only by giving the name.


Thanks,

Aditya

I think this requires a brute force approach:

'c:\','d:\','e:\' | get-childitem -r -filter *.txt -force | where
{!$_.PSIsContainer -and $_.name -eq $filename}

For $filename specify the entire filename that you want to match including
the extension. For the command above I assumed a filter of .txt, change
that to whatever extension the file you're looking for uses.

--
Keith

"AdityaKir" <AdityaKir@xxxxxx> wrote in message
news:39BF9223-4A0E-4715-973E-0211FC44A78B@xxxxxx

Or the same ways one,
in other Windows processes,
uses many other Windows tools
to find files!

Where.exe

The automation (PowerShell) tool's
cmdlet get-command where.exe
returns:

FileDescription:
Where - Lists location of files

Product:
Microsoftr Windowsr Operating System

Or another Windows tool

LogParser.exe -h -i:fs

returns:

Input format: FS (FileSystem properties)
Returns properties of files and folders

Yep there are many Windows tools
(where.exe, powershell.exe, logparser.exe
and etc.) that can help one find files!