Vista - $Variable Is In {1,2,3,4}

I'd like to read from the command line some user input, and then qualify that
they entered a valid response (e.g. "A", "B", or "1"). Is there a
conditional expression that can do this?

Also, I've been searching through Google and MS for about 30 min now looking
for, on the Microsoft site preferably, a comprehensive powershell reference
(where I would have liked to have been able to find the answer to the above
question). I found blogs, script examples, books.... but not just a simple
repository that was comprehensive. Does one exist and can someone give me a
link?

Thank you

$userinput = write-host "Enter something"
if ($userinput -eq "a") { "Valid" } else {"invalid" }


if you want to match more complex strings you can use -match and a regex.

Match a, b or 1 case insensitive:
if ($userinput -match "[a,b,1]")


"C S S" wrote:

On Oct 23, 11:09*am, C S S <C...@xxxxxx> wrote:if ("A", "B","1" -contains $UserInput)

The -contains operator might work backward from the way you usually
check input but it is definitely the way to go in cases like this.
You can add ,'','exit' for example and now an empty string or the word
exit are allowed very simply.

On Oct 23, 12:26*pm, RickB <rbiel...@xxxxxx> wrote:Another handy trick to using this method is:

1..15,'exit' -contains $input

Here any number from 1 thru 15 or 'exit' is allowed.