Vista - get-date - make it a filename

$WshShell = New-Object -ComObject WScript.Shell
$wshshell.run("winzip32 -m 'c:\$(Get-Date -format 'yyyy MMM d').zip'
$dir_source")

I would like my zip file to be "2008 nov 5.zip" ..however powershell zip the
file to "2008.zip"

How can i make the date as part of the file ?

Hello IT,


Try this way:


$fileName = "C:\{0:yyyy MMM d}.zip" -f (get-date)
& winzip32 -m "$fileName" "$dir_source"




---
Shay Levy
Windows PowerShell MVP
http://blogs.microsoft.co.il/blogs/ScriptFanatic
PowerShell Toolbar: http://tinyurl.com/PSToolbar


IS> $WshShell = New-Object -ComObject WScript.Shell
IS> $wshshell.run("winzip32 -m 'c:\$(Get-Date -format 'yyyy MMM d').zip'
IS> $dir_source")
IS>
IS> I would like my zip file to be "2008 nov 5.zip" ..however powershell
IS> zip the file to "2008.zip"
IS>
IS> How can i make the date as part of the file ?
IS>

although $filename looks ok as a string, however

$wshshell.run("winzip32 -m $filename $dir_source") ==> still not able to
recognise full string of $filename.

How can i enscapulate $filename into the Run method ?




"Shay Levy [MVP]" <no@xxxxxx> wrote in message
news:89228ed2505868cb0d49a05a3a6a@xxxxxx

I think the embedded spaces in the filename are messing with the parsing.

Try quoting the $filename, and escaping the quotes with backticks:

$wshshell.run("winzip32 -m `"$filename`" $dir_source")

I try to avoid using filenames with embedded spaces because it tends to
confuse the parser.

"IT Staff" wrote:

yes that is the backtick i m looking for ..thanks



"Rob Campbell" <RobCampbell@xxxxxx> wrote in message
news:C2469850-6802-4E6A-B27B-233081F7AAA3@xxxxxx