Vista - -ne operator

Hi

I have a script that accepts an argument from the user. There are four
possible values that I wish the user to pass to the script. I wil then take
different actions based on the argument passed.
If I do not get one of those values I want to error out. I am not really
sure how to use the the operators.

What I have so far

$Input = $args[0]
If ($Input -ne "1")
{
Write-Host "Error"
Break
}

So here I will break out if I do not get 1 as an input. I also want to error
out if I don't get 2, 3 or 4.

I have tried:
If ($Input -ne "1" -ne "2" -ne "3" -ne "4")
{
Write-Host "Error"
Break
}
but that doesn't work..

Anyone have any tips?

Thanks
Simon

Simon Walsh wrote:Simon,

I would look at the switch statement

Something like this

switch ($input) {

1 {"It’s one"}

2 {"It’s two"}

3 {"It’s three"}

4 {"It’s four"}

default {"Wrong Answer"}
}

Place whatever code you want to execute for each condition in the
corresponding script block.

Regards,

David Muegge

On Nov 23, 7:49*am, David Muegge <da...@xxxxxx> wrote:Another option would be to create an array of valid values like this:

$valid_values = 'one', 'two', 'three', 'radio'

if ($valid_values -notcontains $user_input) {
Write-Error 'Invalid Entry'
}

Thanks for the answers guys
I will try them both out

/Simon
"tojo2000" <tojo2000@xxxxxx> wrote in message
news:be02a293-d1ab-4c57-aeca-33e8b9558d1f@xxxxxx
On Nov 23, 7:49 am, David Muegge <da...@xxxxxx> wrote:Another option would be to create an array of valid values like this:

$valid_values = 'one', 'two', 'three', 'radio'

if ($valid_values -notcontains $user_input) {
Write-Error 'Invalid Entry'
}