Vista - Display an image from powershell?

I need, given a file path to a .jpg or .bmp, to display the image on the
screen. Here is some code I came across on
the net:

$file = (get-item "c:\image.jpg")

[void][reflection.assembly]::LoadWithPartialName("System.Windows.Forms")
$form = new-object Windows.Forms.Form
$form.Text = "Image Viewer"
$form.width = 1280
$form.height = 1024
$pictureBox = new-object Windows.Forms.PictureBox
$pictureBox.Width = 1280
$pictureBox.Height = 1024

$pictureBox.Image = [System.Drawing.Image]::Fromfile($file)
$form.controls.add($pictureBox)
$form.Add_Shown( { $form.Activate() } )
$form.ShowDialog()

I modified the code a little, my problem though is that when
$form.showdialog executes, powershell waits for the dialog results (i.e. a
user to close the dialog). Is there a way for the script to keep executing
and possibly close the dialog itself? Like a simple slide-show type script?

Doesn't matter any more, I found a nice software program for slide shows for
free on the net that works, I have Vista and it has a slideshow program but
it causes tearing when watching videos in WMP (on a second monitor) and
doing a slide show at the same time.

"James" <no@xxxxxx> wrote in message
news:B5E11535-671A-4CF5-BA8A-3CD9E405DD72@xxxxxx