Vista - escape character question - hopefully an easy question

When a string with an escape character is enclosed in double quotes ( ie.
"k`[][][]") , the escape character is removed. With the given example, the
string becomes k[][][]. However, if it is enclosed in single quotes, it
retains the little 'tick'.

I'm working with ADO recordsets and fields of data from access databases
which are returned in the double-quote string format. Is there anyway I can
retain the 'tick' in this situation? I've tried "k`[][][]"
-replace('`','``'), but this does not seem to work. Is there a simple
solution?

I just tried this and it worked

PS> "k`[][][]"
k[][][]
PS> "k``[][][]"
k`[][][]

I don't think the replace will work as the single ` is lost as you build the
string
--
Richard Siddaway
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PowerShell MVP
Blog: http://richardsiddaway.spaces.live.com/
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"Cookiecutter" wrote:

On Jan 28, 7:36*pm, Cookiecutter
<Cookiecut...@xxxxxx> wrote:The reason your replace doesn't work is because the ` is already gone.
IOW it was never really in the string to begin with.
But if you have a string that contains the character then nothing
should remove it without you taking some explicit action.