Vista - Newbie: filter rows with variable

Hi,

I want to call a .ps1 script with a parameter which is used as a
parameter to limit the rows read from a file.
I have tried the following:

ps> list.ps1 <searchcriteria>

list.ps1:
gc c:\temp\test.txt | where {$_ -like "*$args*"} | sort

but I cant get it to work. It does not fail but no rows are returned.

What is wrong here?

Also, when the parameter includes @ (e.g. @work), I get I an error:
Unrecognized token in source text.
At line:1 char:12
+ .\list.ps1 @ <<<< work

How can I avoid this without escaping the @ when entering the
parameter?


thanks,

1) I guess in this context $args is arguments of a script block {$_ -like
"*$args*"} passed into Where-Object cmdlet (but, strange, all lines should
be returned in your example, IMO...). Try this way:

function foo
{
$myArgs = $args
gc <.> | where {$_ -like "*$myArgs*"} | sort
}

foo '<pattern>'

2) Is this OK?:

.\list.ps1 '@work'
or

.\list.ps1 "@work"

--
Thanks,
Roman Kuzmin

This is known issue... I cannot recall exactly what the exact issue is, but
I know I have it baked in my brain never to use $args directly.

"Roman Kuzmin" <z@z.z> wrote in message
news:edDzeZhlHHA.4032@TK2MSFTNGP02.phx.gbl...
> 1) I guess in this context $args is arguments of a script block {$_ -like
> "*$args*"} passed into Where-Object cmdlet (but, strange, all lines should
> be returned in your example, IMO...). Try this way:
>
> function foo
> {
> $myArgs = $args
> gc <.> | where {$_ -like "*$myArgs*"} | sort
> }
>
> foo '<pattern>'
>
> 2) Is this OK?:
>
> .\list.ps1 '@work'
> or
>
> .\list.ps1 "@work"
>
> --
> Thanks,
> Roman Kuzmin
>
>

On May 14, 12:55 pm, "Roman Kuzmin" <z...@z.z> wrote:
> 1) I guess in this context $args is arguments of a script block {$_ -like
> "*$args*"} passed into Where-Object cmdlet (but, strange, all lines should
> be returned in your example, IMO...). Try this way:
>
> function foo
> {
> $myArgs = $args
> gc <.> | where {$_ -like "*$myArgs*"} | sort
> }
>
> foo '<pattern>'
>
> 2) Is this OK?:
>
> .\list.ps1 '@work'
> or
>
> .\list.ps1 "@work"
>
> --
> Thanks,
> Roman Kuzmin

Hi,

assigning $args to $myargs actually worked :-). Thanks for this.

Calling the script with @work or "@work" returns the error I mention
in the first post.
Calling the script with '@work' (singlequotes) does return the
expected output. But how should I "prepare" my $args so that I do not
have to specify the singlequotes in the parameter?

I tried

$myargs=$args
$myargs = "'"+$myargs+"'"

but that returns the same errormessage as earlier mentioned.

Thanks,