Vista Tutorial - A array problem

in this little command i want to access a element of a array: please look

for ($a=0; $a -le 8; $a++) {dsadd group
"CN=$hn$b[$a],OU=local,OU=roles,DC=cz,DC=int-e,DC=kaufland" -scope l

The output of the defined variable $hn is ok, but when i want to access
$b[$a] variable, the array will output his whole content. Do I have to
mascerade my $b variable?

Any help is welcome?
THX

try this
"CN=$($hn)$($b[$a]),OU=local,OU=roles,DC=cz,DC=int-e,DC=kaufland"

The "$( )" Expands the result of $b[$a] and outputs the string instead.

"Jens Diekers" <Jens Diekers@discussions.microsoft.com> wrote in message
news:2E8F00FF-EFD5-4874-982A-6635B4CC585F@microsoft.com...
> in this little command i want to access a element of a array: please look
>
> for ($a=0; $a -le 8; $a++) {dsadd group
> "CN=$hn$b[$a],OU=local,OU=roles,DC=cz,DC=int-e,DC=kaufland" -scope l
>
> The output of the defined variable $hn is ok, but when i want to access
> $b[$a] variable, the array will output his whole content. Do I have to
> mascerade my $b variable?
>
> Any help is welcome?
> THX

Jens Diekers wrote:
> in this little command i want to access a element of a array: please look
>
> for ($a=0; $a -le 8; $a++) {dsadd group
> "CN=$hn$b[$a],OU=local,OU=roles,DC=cz,DC=int-e,DC=kaufland" -scope l
>
> The output of the defined variable $hn is ok, but when i want to access
> $b[$a] variable, the array will output his whole content. Do I have to
> mascerade my $b variable?
>
> Any help is welcome?
> THX

It could be $b is a string or something else other than an array.
Before doing your loop, what does "$b.gettype()" give?

Marco

------------------
PowerGadgets MVP
http://www.powergadgets.com/mvp

p.s. Also... Im not entirely sure what your goal is by $a -le 8, but if you
just want to do it for each element in $b

foreach($element in $b)
{
"CN=$hn$element,OU=local,OU=roles,DC=cz,DC=int-e,DC=kaufland" -scope l
}
"Jens Diekers" <Jens Diekers@discussions.microsoft.com> wrote in message
news:2E8F00FF-EFD5-4874-982A-6635B4CC585F@microsoft.com...
> in this little command i want to access a element of a array: please look
>
> for ($a=0; $a -le 8; $a++) {dsadd group
> "CN=$hn$b[$a],OU=local,OU=roles,DC=cz,DC=int-e,DC=kaufland" -scope l
>
> The output of the defined variable $hn is ok, but when i want to access
> $b[$a] variable, the array will output his whole content. Do I have to
> mascerade my $b variable?
>
> Any help is welcome?
> THX

Thank you Brandon and Marco! This Solutions is very effective for my PS
Script. I hope I can help you next time.

P.S. Marco: the b variable returns marketcodes...

Great Support...