Vista Tutorial - echo output

Hello again,

i think i have another basic question.

i will make a array like this:

$mn = 123
$x = echo $mn, ($mn)STRING...

i want that my out looks like this:
123
123STRING..., but the STRING... is interpreted as the third part of the
array. It looks like this
123
123
STRING...


What can i do?

THX

$nm = 123
$x = $nm,"$nm `bSTRING"

You dont need echo and `b is a backspace. If you use "" variables are
expanded.

"Jens Diekers" <JensDiekers@discussions.microsoft.com> wrote in message
news:CEA606D9-F2FF-45ED-9533-2CD77929F0B0@microsoft.com...
> Hello again,
>
> i think i have another basic question.
>
> i will make a array like this:
>
> $mn = 123
> $x = echo $mn, ($mn)STRING...
>
> i want that my out looks like this:
> 123
> 123STRING..., but the STRING... is interpreted as the third part of the
> array. It looks like this
> 123
> 123
> STRING...
>
>
> What can i do?
>
> THX

On Aug 13, 7:34 am, Jens Diekers
<JensDiek...@discussions.microsoft.com> wrote:
> Hello again,
>
> i think i have another basic question.
>
> i will make a array like this:
>
> $mn = 123
> $x = echo $mn, ($mn)STRING...
>
> i want that my out looks like this:
> 123
> 123STRING..., but the STRING... is interpreted as the third part of the
> array. It looks like this
> 123
> 123
> STRING...
>
> What can i do?
>
> THX

Personally, I like to use this syntax for simple variable
substitution:

PS> $s = "string"
PS> "${s}test"
stringtest

Note the use of curly braces to delimit the variable name. However,
this doesn't work for grabbing an object's property:

PS> "${s.length}test"
test

Doh.

So in this case, I use a new evaluation context like so:

PS> "$($s.length)test"
6test

They're ordinary brackets this time, not the curly ones.

Hope this helps,

- Oisin