Vista - Position in an array

I have an array that contains numbers 1 through 10 in a random order: (4, 2,
8, 7, 1, 9, 10, 3, 5, 6). I would like to know if there is a function that I
can call that will take an input of an element in the array and return its
position.

FunctionName(5) would return 9 since 5 is the 9th element of the array.

Thanks for your help.

My solution to your problem would be to use an arraylist instead:


[System.Collections.ArrayList]$foo = 4, 2, 8, 7, 1, 9, 10, 3, 5, 6
$foo.IndexOf(5)

"bugiwan" wrote:

In PowerShell arrays are zero based. The first element's index is 0.

$arr = 4, 2, 8, 7, 1, 9, 10, 3, 5, 6

# You can call the IndexOf Static Method

[array]::indexOf($arr, 5)

# ... or create a function:

function IndexOf ([object[]]$array, $element)
{
0..($array.length - 1) | where {$array[$_] -eq $element}
}

IndexOf $arr 5

--
Kiron

Nice. It did seem silly that the array object would not have that
functionality but a quick search didn't turn it up and I knew that arraylist
did so I suggested that.

"Kiron" wrote:

Thanks. Your solution gets it done too!
--
Kiron

Thanks. Your solution gets it done too!
Nice concurrent posts by the way.

--
Kiron