Vista - A little math

I am trying to write a vbscript that does some basic math. I want to
be able to input a number and let the logic in the script tell me if
the number is zero, less than one thousand, or greater than or equal
to one thousand. The script I have written to do this is below:

'*************************Getting the file system
object*************************
Set oFSO = WScript.CreateObject("Scripting.FileSystemObject")
Set objShell = CreateObject("WScript.Shell")
strComputer = "."

IntGrpMembers = InputBox ("Enter a number.")


If IntGrpMembers ="0" Then

Wscript.echo IntGrpMembers & " is equal to zero." &VbCrLf

ElseIf IntGrpMembers <"1000" Then

Wscript.echo IntGrpMembers & " is less than one thousand." &VbCrLf

ElseIf IntGrpMembers >="1000" Then

Wscript.echo IntGrpMembers & " is greater than or equal to 1000."
&VbCrLf

else

Wscript.echo IntGrpMembers & " did not fall with in the expected
criteria." &VbCrLf

End IF

The problem I found is that my logic isn’t working quite like I
thought it would. When I run the script and I input a value of 2 I
get back, “2 is greater than or equal to 1000.” That’s just not
right. Will someone please help me figure out what I am doing wrong.

Thanks,

Keith

On Mar 9, 10:06*am, keith <keith...@xxxxxx> wrote:Your logic is making string comparisons. In such cases the result is
more akin to sorting, where "2" will come after "1000" - that is, it's
greater than "1000".

Just remove the quotes around the literal constants in the IF
statements and it should work fine. Well, there is one more thing -
change your input line to force the result to be numeric. One way is
to add zero to it (the inelegant way I normally use). Or use the more
elegant ...

IntGrpMembers = CSng(InputBox ("Enter a number."))

Tom Lavedas
***********
http://there.is.no.more/tglbatch/

Expanding on Tom's response a bit, you want to change ALL your numeric
lookups to integer values, and force them where necessary. Specifically, I
would use the following for the IntGrpMembers entry:

IntGrpMembers = CInt(InputBox ("Enter a number."))

If you don't do this, whatever is entered into the inputbox will be
interpreted as a string by default.

"keith" <keithlr2@xxxxxx> wrote in message
news:873edcc5-2390-4474-8387-884d2b77f601@xxxxxx