Vista - VBscript to generate memory load

Hi...

I'd like some help, is it possible to write a vbscript that can
generate some memory load on a server.

I know there's a vbscript called cpubusy.vbs which can be used to
generate cpu load on a server. Is there something equivalent for RAM
load I can use for testing....


Cheers Thanks

"Star" <momo2804@xxxxxx> wrote in message
news:3bfab76f-5d3e-417a-95d8-ae017304df9e@xxxxxxYou could repeatedly read some data into memory, e.g. like so:

Set oFSO = CreateObject("Scripting.FileSystemObject")
Dim aData(10)
Set oFile = oFSO.OpenTextFile("e:\test.bin")
aData(0) = oFile.ReadAll
oFile.Close
For i = 1 To 9
aData(i) = aData(0)
Next
MsgBox "Click OK to exit"

The following command will instantly create a disk file of any size, e.g. 10
or 100 MBytes:

fsutil file createnew test.bin 10000000

"Pegasus [MVP]" <news@xxxxxx> wrote in message
news:uUvahQt0JHA.1432@xxxxxxThat would seem to create a "disk load" rather than a "RAM load", though,
wouldn't it?

Of course, it is not clear what would actually constitute a "load" on
memory. Your 2G of memory is completely full of some combination of bit
values. It does not matter what these values are, as it takes no more energy
to maintain ones as it takes to maintain zeros.

You could write a script to change a bunch of these values, but the main
effect would seem to be the "CPU load" involved in making those changes.

What is it that you are trying to accomplish here?

/Al

"Al Dunbar" <alandrub@xxxxxx> wrote in message
news:uMrVxnw0JHA.140@xxxxxxReading ten copies of a 100 MByte file into memory would IMHO load 1 GBytes
of data into memory, with Windows deciding whether it should go into RAM or
into the Paging File.

On May 12, 10:52*am, "Pegasus [MVP]" <n...@xxxxxx> wrote:Why do they need to be read from a file? I think that was Al's point,
at least in part. He also suggests that zeros are as good as ones, so
just defining a large array would occupy the memory just as well.

Finally, I reinforce his question about what the OP is trying to
accomplish - since as you point out - Windows may or may not actually
use RAM for the transaction, anyway.

Tom Lavedas
***********

"T Lavedas" <tglbatch@xxxxxx> wrote in message
news:b265d27d-4b96-47ff-ad6f-39561603add3@xxxxxx
On May 12, 10:52 am, "Pegasus [MVP]" <n...@xxxxxx> wrote:Why do they need to be read from a file? I think that was Al's point,
at least in part.
*** Agreed - reading them from a file is one of several methods.

He also suggests that zeros are as good as ones, so
just defining a large array would occupy the memory just as well.
*** When you say "define", do you mean "declare" or "populate"?
*** If you mean "declare" then we don't know for sure at what
*** time the interpreter grabs the memory.

Finally, I reinforce his question about what the OP is trying to
accomplish - since as you point out - Windows may or may not actually
use RAM for the transaction, anyway.

Tom Lavedas
***********

Thanks guys for all your replies, actually the reason I'm doing this
is because I'm doing some testing on VMware and I want to stress out
the load on the VMs to see how the VMware will handle when there's
memory among VMs.

Cheers........

"Pegasus [MVP]" <news@xxxxxx> wrote in message
news:O7Bxogx0JHA.4756@xxxxxxBut if one needs to generate a "load" on one component (i.e. memory), then
including another component that can be a bottleneck (i.e. disk I/O) would
tend to reduce the rate at which memory is "loaded". Perhaps.

Actually, all I meant was that the "stress" or "load" you put on available
memory is no higher when it is ones you are storing than when it is zeros.
But it still comes down to this: what does it mean to place a "load" on
memory? The concept makes no sense to me.
Not exactly true. We do know for a fact that [DIM A(999999)] does not
allocate any space for the elements that will make up the array, though it
may allocate space for indexing. If we then define A(555555) to be a large
object, this does not cause any other elements of the array to take on
storage.
I would also ask what he means by placing a load on memory.

/Al

<momo2804@xxxxxx> wrote in message
news:809670f6-677f-4cab-b63e-34da3e881deb@xxxxxxDo you want to "load" the memory of the host machine, or of the virtual
machines? Does this mean that you want to run a program that "occupies" a
large chunk of memory, therefore reducing the amount available for competing
programs? Or do you want to "exercise" that memory by storing data into it
and then perhaps changing it?

Until you define precisely what it is that is required (i.e or that you mean
by creating a "load" on memory), we are unlikely to come up with a solution.

And, as Tom mentioned a bit earlier, you may not always know what memory
operations windows might be performing on disk and vice-versa. Adding vmware
to the mix is simply adding two more layers of vagueness to the mix.


/Al